lnx-2[ln(x+2)+ln(x-2)]=0

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Solution for lnx-2[ln(x+2)+ln(x-2)]=0 equation:


Simplifying
lnx + -2[ln(x + 2) + ln(x + -2)] = 0

Reorder the terms:
lnx + -2[ln(2 + x) + ln(x + -2)] = 0
lnx + -2[(2 * ln + x * ln) + ln(x + -2)] = 0
lnx + -2[(2ln + lnx) + ln(x + -2)] = 0

Reorder the terms:
lnx + -2[2ln + lnx + ln(-2 + x)] = 0
lnx + -2[2ln + lnx + (-2 * ln + x * ln)] = 0
lnx + -2[2ln + lnx + (-2ln + lnx)] = 0

Reorder the terms:
lnx + -2[2ln + -2ln + lnx + lnx] = 0

Combine like terms: 2ln + -2ln = 0
lnx + -2[0 + lnx + lnx] = 0
lnx + -2[lnx + lnx] = 0

Combine like terms: lnx + lnx = 2lnx
lnx + -2[2lnx] = 0

Remove brackets around [2lnx]
lnx + -2 * 2lnx = 0

Multiply -2 * 2
lnx + -4lnx = 0

Combine like terms: lnx + -4lnx = -3lnx
-3lnx = 0

Solving
-3lnx = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '-3'.
lnx = 0

Simplifying
lnx = 0

The solution to this equation could not be determined.

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